WebDec 4, 2016 · Info given: Consider a direct-mapped cache with 16KBytes of storage and a block size of 16 bytes. Assume that the address size is 32 bits. So I've done the calculation and get a total number of 32 bits required. We were given the following formula: (bits/tag) + (bits/index) + (bits/block offset) = total number of bits. WebApr 21, 2024 · Well, the block height can take 256 values and each block uses at most ~2.5 bytes, so it's 12550824*12550824*256*2.5 = 100,814,837,170,544,640 bytes, aka 100,815,000 GB, aka 101 petabytes. You're going to need a bigger disk ;) Compression could reduce this somewhat, but depends heavily on the complexity of the world.
computer architecture - How to calculate the number of tag, index …
WebAug 26, 2016 · There would be 34 records each 115 bytes in a 4k block. That would utilize 3910 bytes (+ 100 for our header information). Only 86 bytes would be wasted and 30 record slots would be unused. Assuming these records don't grow, this would mean that ~148,972 KB of this Storage Area are unused (60309414 records / 34 rpb x 86 bytes) WebAnswer Since the cache is direct-mapped, the size of the set is 256 bits (?) = 32 byte and therefore it takes 5 bits to address the memory, so the number of bits that are not the tag is 5 (?) = 27 bits are used for the tag (?) Since a line is 2 words = 64 bits (?) = 8 byte then the offset takes 3 bytes and therefore the block takes 2 bytes (?). sickness pay entitlement nhs
Solved 4. Offset bits tell us how many bytes of data are in
WebOne byte can hold a number between 0 and 255 i.e. with 256 different patterns, we can store a number in the range 0..255 Really good for storing characters/letters. Bytes "Byte" - unit of information storage A document, … WebMay 30, 2024 · The block size is 4KB, the block address length is 4 bytes and the i-nodes have a traditional structure (10 direct pointers, 1 indirect pointer, 1 double indirect pointer and 1 triple indirect pointer). What is the number of blocks (including both the data and address blocks) occupied by the following files: File A with a size of 20 KBytes WebAug 17, 2024 · You can convert 512 byte blocks to bytes by multiplying them by 512. For example, six 512-byte-blocks multiplied by 512 equals 3,072 bytes. How much data is a … sickness overrides holiday